We are given two matrices $A$ and $B$, where $A = \begin{bmatrix} 2 & 1 & 0 \\ 7 & 2 & 8 \\ 1 & 0 & 4 \end{bmatrix}$ and $B = \begin{bmatrix} 1 & 1 & 4 & 0 \\ 8 & 3 & 1 & 1 \\ 1 & 3 & 2 & 0 \end{bmatrix}$. We need to find the matrix product $BA$.

1. Problem Description

We are given two matrices $A$ and $B$, where

$A = \begin{bmatrix} 2 & 1 & 0 \\ 7 & 2 & 8 \\ 1 & 0 & 4 \end{bmatrix}$ and $B = \begin{bmatrix} 1 & 1 & 4 & 0 \\ 8 & 3 & 1 & 1 \\ 1 & 3 & 2 & 0 \end{bmatrix}$.

We need to find the matrix product $BA$.

2. Solution Steps

The matrix $B$ is a $3 \times 4$ matrix and $A$ is a $3 \times 3$ matrix. For the matrix product $BA$ to be defined, the number of columns in $B$ must equal the number of rows in $A$. However, $B$ has 4 columns and $A$ has 3 rows. Thus, the product $BA$ is not defined, i.e. impossible.

3. Final Answer

IMPOSSIBLE