The problem asks to rewrite the logarithmic function $y = \log_3(x)$ using the change-of-base formula and base $e$ logarithms (natural logarithms).

AlgebraLogarithmsChange of BaseNatural Logarithm
2025/3/8

1. Problem Description

The problem asks to rewrite the logarithmic function y=log3(x)y = \log_3(x) using the change-of-base formula and base ee logarithms (natural logarithms).

2. Solution Steps

The change-of-base formula states that for any positive numbers aa, bb, and xx where a1a \neq 1 and b1b \neq 1,
loga(x)=logb(x)logb(a)\log_a(x) = \frac{\log_b(x)}{\log_b(a)}
In our case, we want to rewrite y=log3(x)y = \log_3(x) using base ee (natural logarithms). So, a=3a = 3, x=xx = x, and b=eb = e. Therefore, we have:
log3(x)=loge(x)loge(3)\log_3(x) = \frac{\log_e(x)}{\log_e(3)}
Since loge(x)\log_e(x) is the natural logarithm of xx, we can write it as ln(x)\ln(x). Therefore,
log3(x)=ln(x)ln(3)\log_3(x) = \frac{\ln(x)}{\ln(3)}
So, the expression for yy becomes:
y=ln(x)ln(3)y = \frac{\ln(x)}{\ln(3)}

3. Final Answer

y=ln(x)ln(3)y = \frac{\ln(x)}{\ln(3)}

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