The problem asks us to solve the exponential equation $6^{3x} = 7776$ for $x$ and provide the answer correct to 3 decimal places.

AlgebraExponential EquationsLogarithmsSolving Equations
2025/3/8

1. Problem Description

The problem asks us to solve the exponential equation 63x=77766^{3x} = 7776 for xx and provide the answer correct to 3 decimal places.

2. Solution Steps

To solve the equation 63x=77766^{3x} = 7776, we can take the natural logarithm of both sides of the equation:
ln(63x)=ln(7776)\ln(6^{3x}) = \ln(7776)
Using the property of logarithms that ln(ab)=bln(a)\ln(a^b) = b\ln(a), we have:
3xln(6)=ln(7776)3x \ln(6) = \ln(7776)
Now, we can isolate xx by dividing both sides by 3ln(6)3\ln(6):
x=ln(7776)3ln(6)x = \frac{\ln(7776)}{3\ln(6)}
Now, we use a calculator to evaluate the expression:
ln(7776)8.95805\ln(7776) \approx 8.95805
ln(6)1.79176\ln(6) \approx 1.79176
3ln(6)5.375283 \ln(6) \approx 5.37528
x8.958055.375281.66652x \approx \frac{8.95805}{5.37528} \approx 1.66652
Rounding the result to three decimal places, we have:
x1.667x \approx 1.667

3. Final Answer

x=1.667x = 1.667

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