We are asked to solve the equation $95000 = 10000(1.05)^{4x}$ for $x$ and give the answer correct to 3 decimal places.

AlgebraExponential EquationsLogarithmsSolving Equations
2025/3/8

1. Problem Description

We are asked to solve the equation 95000=10000(1.05)4x95000 = 10000(1.05)^{4x} for xx and give the answer correct to 3 decimal places.

2. Solution Steps

We start with the given equation:
95000=10000(1.05)4x95000 = 10000(1.05)^{4x}
First, divide both sides by 10000:
9500010000=(1.05)4x\frac{95000}{10000} = (1.05)^{4x}
9.5=(1.05)4x9.5 = (1.05)^{4x}
Next, take the natural logarithm (ln) of both sides:
ln(9.5)=ln((1.05)4x)\ln(9.5) = \ln((1.05)^{4x})
Using the property of logarithms, ln(ab)=bln(a)\ln(a^b) = b\ln(a), we have:
ln(9.5)=4xln(1.05)\ln(9.5) = 4x \ln(1.05)
Now, solve for xx by dividing both sides by 4ln(1.05)4 \ln(1.05):
x=ln(9.5)4ln(1.05)x = \frac{\ln(9.5)}{4 \ln(1.05)}
Using a calculator to find the values of the logarithms:
ln(9.5)2.25129\ln(9.5) \approx 2.25129
ln(1.05)0.04879\ln(1.05) \approx 0.04879
Substitute these values into the equation for xx:
x=2.251294(0.04879)x = \frac{2.25129}{4(0.04879)}
x=2.251290.19516x = \frac{2.25129}{0.19516}
x11.5355x \approx 11.5355
Rounding to 3 decimal places, we have:
x11.536x \approx 11.536

3. Final Answer

x=ln(9.5)4ln(1.05)11.536x = \frac{\ln(9.5)}{4\ln(1.05)} \approx 11.536

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