The problem provides a table of $x$ and $y$ values related to the function $y = (x-2)^2 - a$. The task is to find the value of $a$ based on the given data. From the table, when $x=0$, $y=1$.

AlgebraQuadratic FunctionsFunction EvaluationSolving Equations
2025/6/1

1. Problem Description

The problem provides a table of xx and yy values related to the function y=(x2)2ay = (x-2)^2 - a. The task is to find the value of aa based on the given data. From the table, when x=0x=0, y=1y=1.

2. Solution Steps

We are given the function y=(x2)2ay = (x-2)^2 - a.
We have a pair of xx and yy values from the table, such as when x=0x=0, y=1y=1.
Substitute x=0x=0 and y=1y=1 into the equation:
1=(02)2a1 = (0-2)^2 - a
1=(2)2a1 = (-2)^2 - a
1=4a1 = 4 - a
a=41a = 4 - 1
a=3a = 3

3. Final Answer

The value of aa is 3.

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