The problem asks us to find the slope and y-intercept of a given line, and then write the equation of the line in slope-intercept form ($y = mx + b$). We are given that the y-intercept is at $(0,1)$ and the slope of the line is $\frac{5}{2}$.

AlgebraLinear EquationsSlope-intercept form
2025/3/6

1. Problem Description

The problem asks us to find the slope and y-intercept of a given line, and then write the equation of the line in slope-intercept form (y=mx+by = mx + b). We are given that the y-intercept is at (0,1)(0,1) and the slope of the line is 52\frac{5}{2}.

2. Solution Steps

The slope-intercept form of a line is given by:
y=mx+by = mx + b
where mm is the slope and bb is the y-intercept.
We are given that the y-intercept is (0,1)(0, 1), so b=1b = 1.
We are also given that the slope is m=52m = \frac{5}{2}.
Substituting these values into the slope-intercept form, we get:
y=52x+1y = \frac{5}{2}x + 1

3. Final Answer

y=52x+1y = \frac{5}{2}x + 1

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