The problem asks to find the slope and $y$-intercept of the line shown in the graph, and then write the equation of the line.

1. Problem Description

The problem asks to find the slope and $y$-intercept of the line shown in the graph, and then write the equation of the line.

2. Solution Steps

First, we need to find two points on the line. From the graph, we can identify two points as $(0, 12)$ and $(6, 2)$.

The slope $m$ of the line passing through points $(x_1, y_1)$ and $(x_2, y_2)$ is given by:

$m = \frac{y_2 - y_1}{x_2 - x_1}$

Using the points $(0, 12)$ and $(6, 2)$, we have:

$m = \frac{2 - 12}{6 - 0} = \frac{-10}{6} = -\frac{5}{3}$

The $y$-intercept $b$ is the $y$-coordinate of the point where the line intersects the $y$-axis. From the graph, the line intersects the $y$-axis at $(0, 12)$, so $b = 12$.

The equation of a line in slope-intercept form is given by:

$y = mx + b$

Substituting $m = -\frac{5}{3}$ and $b = 12$ into the equation, we get:

$y = -\frac{5}{3}x + 12$

3. Final Answer

$y = -\frac{5}{3}x + 12$

Slope = $-\frac{5}{3}$