The problem asks to find the slope and y-intercept of a line from its graph, and then use these to write the equation of the line in slope-intercept form. The slope is given as $8/-5$ and the y-intercept is given as $(0,0)$.

1. Problem Description

The problem asks to find the slope and y-intercept of a line from its graph, and then use these to write the equation of the line in slope-intercept form. The slope is given as $8/-5$ and the y-intercept is given as $(0,0)$.

2. Solution Steps

First, simplify the slope. $8/-5$ can be written as $-8/5$.

Next, we're given the y-intercept as $(0, 0)$. This means the line crosses the y-axis at the point where $y = 0$.

The slope-intercept form of a linear equation is:

$y = mx + b$

where $m$ is the slope and $b$ is the y-intercept.

In this case, $m = -8/5$ and $b = 0$.

Plugging these values into the slope-intercept form, we get:

$y = (-8/5)x + 0$

Which simplifies to:

$y = (-8/5)x$

3. Final Answer

$y = -\frac{8}{5}x$