The problem consists of two questions. Question 1 asks to rewrite expressions with negative exponents as equivalent expressions with positive exponents. Question 2 asks to evaluate some expressions.

AlgebraExponentsAlgebraic ExpressionsSimplification
2025/6/16

1. Problem Description

The problem consists of two questions.
Question 1 asks to rewrite expressions with negative exponents as equivalent expressions with positive exponents.
Question 2 asks to evaluate some expressions.

2. Solution Steps

Question 1:
i. 53=1535^{-3} = \frac{1}{5^3}
ii. (13)2=(31)2=32(\frac{1}{3})^{-2} = (\frac{3}{1})^2 = 3^2
iii. (0.2)4=(210)4=(15)4=(51)4=54(0.2)^{-4} = (\frac{2}{10})^{-4} = (\frac{1}{5})^{-4} = (\frac{5}{1})^4 = 5^4
iv. x4=1x4x^{-4} = \frac{1}{x^4}
v. (24)2=(12)2=(21)2=22(\frac{2}{4})^{-2} = (\frac{1}{2})^{-2} = (\frac{2}{1})^2 = 2^2
Question 2:
i. 43×4=43×41=43+1=44=2564^3 \times 4 = 4^3 \times 4^1 = 4^{3+1} = 4^4 = 256
ii. 35×34=35+(4)=354=31=33^5 \times 3^{-4} = 3^{5+(-4)} = 3^{5-4} = 3^1 = 3
iii. 5858=588=50=1\frac{5^8}{5^8} = 5^{8-8} = 5^0 = 1

3. Final Answer

Question 1:
i. 153\frac{1}{5^3}
ii. 323^2
iii. 545^4
iv. 1x4\frac{1}{x^4}
v. 222^2
Question 2:
i. 256256
ii. 33
iii. 11

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