The problem is to factorize the expression $8x^3 + y^3$. This is a sum of cubes.

AlgebraFactorizationSum of CubesPolynomials
2025/6/16

1. Problem Description

The problem is to factorize the expression 8x3+y38x^3 + y^3. This is a sum of cubes.

2. Solution Steps

We are given the expression 8x3+y38x^3 + y^3. We can rewrite 8x38x^3 as (2x)3(2x)^3. So, we have (2x)3+y3(2x)^3 + y^3.
We use the sum of cubes factorization formula:
a3+b3=(a+b)(a2ab+b2)a^3 + b^3 = (a+b)(a^2 - ab + b^2).
In this case, a=2xa = 2x and b=yb = y. Substituting these values into the formula gives us:
(2x)3+y3=(2x+y)((2x)2(2x)(y)+y2)(2x)^3 + y^3 = (2x + y)((2x)^2 - (2x)(y) + y^2).
Simplifying the terms inside the second parenthesis, we get:
(2x)3+y3=(2x+y)(4x22xy+y2)(2x)^3 + y^3 = (2x + y)(4x^2 - 2xy + y^2).

3. Final Answer

The factored form of the expression 8x3+y38x^3 + y^3 is (2x+y)(4x22xy+y2)(2x + y)(4x^2 - 2xy + y^2).

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