The problem asks to solve the linear equation $\frac{b}{3} + 15 = -8$ for the variable $b$.

AlgebraLinear EquationsSolving EquationsAlgebraic Manipulation
2025/3/9

1. Problem Description

The problem asks to solve the linear equation b3+15=8\frac{b}{3} + 15 = -8 for the variable bb.

2. Solution Steps

We are given the equation b3+15=8\frac{b}{3} + 15 = -8.
First, we subtract 1515 from both sides of the equation:
b3+1515=815\frac{b}{3} + 15 - 15 = -8 - 15
b3=23\frac{b}{3} = -23
Next, we multiply both sides of the equation by 33:
3×b3=3×(23)3 \times \frac{b}{3} = 3 \times (-23)
b=69b = -69

3. Final Answer

b=69b = -69

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