The problem states that $Z$ is the centroid of triangle $TRS$. Given that $TO = 7b + 5$, $OR = 13b - 10$, and $TR = 18b$, we need to find the value of $b$ and the length of $TR$. Since $Z$ is the centroid, $O$ is the midpoint of side $TR$, which means $TO = OR$.

GeometryCentroidTriangleMidpointAlgebraic EquationsLine Segments
2025/7/1

1. Problem Description

The problem states that ZZ is the centroid of triangle TRSTRS. Given that TO=7b+5TO = 7b + 5, OR=13b10OR = 13b - 10, and TR=18bTR = 18b, we need to find the value of bb and the length of TRTR. Since ZZ is the centroid, OO is the midpoint of side TRTR, which means TO=ORTO = OR.

2. Solution Steps

Since OO is the midpoint of TRTR, TO=ORTO = OR. We can set up the equation:
7b+5=13b107b + 5 = 13b - 10
Subtract 7b7b from both sides:
5=6b105 = 6b - 10
Add 1010 to both sides:
15=6b15 = 6b
Divide both sides by 66:
b=156=52=2.5b = \frac{15}{6} = \frac{5}{2} = 2.5
Now we can find the length of TRTR:
TR=18b=18×52=9×5=45TR = 18b = 18 \times \frac{5}{2} = 9 \times 5 = 45

3. Final Answer

b=2.5b = 2.5
TR=45TR = 45

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