The problem asks us to find the inverse function $f^{-1}(y)$ given the function $f(x) = 8(x-2) + 4$.

AlgebraInverse FunctionsLinear FunctionsFunction Transformation
2025/7/3

1. Problem Description

The problem asks us to find the inverse function f1(y)f^{-1}(y) given the function f(x)=8(x2)+4f(x) = 8(x-2) + 4.

2. Solution Steps

To find the inverse function f1(y)f^{-1}(y), we first replace f(x)f(x) with yy, so we have:
y=8(x2)+4y = 8(x-2) + 4
Now we solve for xx in terms of yy:
y=8x16+4y = 8x - 16 + 4
y=8x12y = 8x - 12
y+12=8xy + 12 = 8x
x=y+128x = \frac{y + 12}{8}
Now we replace xx with f1(y)f^{-1}(y):
f1(y)=y+128f^{-1}(y) = \frac{y + 12}{8}

3. Final Answer

f1(y)=y+128f^{-1}(y) = \frac{y+12}{8}

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