The problem asks to evaluate $\tan(\frac{\pi}{3})$.

1. Problem Description

The problem asks to evaluate $\tan(\frac{\pi}{3})$.

2. Solution Steps

We need to find the value of the tangent function at $\frac{\pi}{3}$ radians.

Recall that $\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}$.

First, we find $\sin(\frac{\pi}{3})$ and $\cos(\frac{\pi}{3})$.

We know that $\frac{\pi}{3}$ radians is equal to $60^\circ$.

$\sin(\frac{\pi}{3}) = \sin(60^\circ) = \frac{\sqrt{3}}{2}$

$\cos(\frac{\pi}{3}) = \cos(60^\circ) = \frac{1}{2}$

Therefore,

$\tan(\frac{\pi}{3}) = \frac{\sin(\frac{\pi}{3})}{\cos(\frac{\pi}{3})} = \frac{\frac{\sqrt{3}}{2}}{\frac{1}{2}} = \frac{\sqrt{3}}{2} \cdot \frac{2}{1} = \sqrt{3}$.

3. Final Answer

$\sqrt{3}$