The image contains four problems and one bonus problem related to finding the slope of a line. Problem 1: Find the slope of the line given a table of points: $x = -1, 2, 5, 8$ and $y = 3, -1, -5, -9$. Problem 2: Find the slope of the line given a table of points: $x = 2, 8, 13$ and $y = -1, 0, 1$. Problem 3: Find the slope of the line passing through the points G$(-1, 2)$ and H$(7, 2)$. Problem 4: Find the slope of the line passing through the points F$(6, 8)$ and f$(6, -2)$. Bonus Problem: A student calculates the slope of the line passing through the points $(-3, 8)$ and $(2, -4)$ as $m = \frac{-3-8}{2-(-4)} = \frac{-11}{6}$. Identify the mistake and correct it.

AlgebraLinear EquationsSlopeCoordinate GeometryPointsUndefined Slope
2025/4/15

1. Problem Description

The image contains four problems and one bonus problem related to finding the slope of a line.
Problem 1: Find the slope of the line given a table of points: x=1,2,5,8x = -1, 2, 5, 8 and y=3,1,5,9y = 3, -1, -5, -9.
Problem 2: Find the slope of the line given a table of points: x=2,8,13x = 2, 8, 13 and y=1,0,1y = -1, 0, 1.
Problem 3: Find the slope of the line passing through the points G(1,2)(-1, 2) and H(7,2)(7, 2).
Problem 4: Find the slope of the line passing through the points F(6,8)(6, 8) and f(6,2)(6, -2).
Bonus Problem: A student calculates the slope of the line passing through the points (3,8)(-3, 8) and (2,4)(2, -4) as m=382(4)=116m = \frac{-3-8}{2-(-4)} = \frac{-11}{6}. Identify the mistake and correct it.

2. Solution Steps

Problem 1:
We can use any two points from the table to find the slope. Let's use the first two points: (1,3)(-1, 3) and (2,1)(2, -1).
The formula for slope is:
m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}
m=132(1)=43m = \frac{-1 - 3}{2 - (-1)} = \frac{-4}{3}
Problem 2:
Using the first two points: (2,1)(2, -1) and (8,0)(8, 0).
m=0(1)82=16m = \frac{0 - (-1)}{8 - 2} = \frac{1}{6}
Problem 3:
Given points G(1,2)(-1, 2) and H(7,2)(7, 2).
m=227(1)=08=0m = \frac{2 - 2}{7 - (-1)} = \frac{0}{8} = 0
Problem 4:
Given points F(6,8)(6, 8) and f(6,2)(6, -2).
m=2866=100m = \frac{-2 - 8}{6 - 6} = \frac{-10}{0}
The slope is undefined since division by zero is not allowed.
Bonus Problem:
The student incorrectly substituted the x-coordinates for the y-coordinates in the numerator. The correct formula for slope is m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}.
Using the points (3,8)(-3, 8) and (2,4)(2, -4):
m=482(3)=125m = \frac{-4 - 8}{2 - (-3)} = \frac{-12}{5}

3. Final Answer

Problem 1: m=43m = -\frac{4}{3}
Problem 2: m=16m = \frac{1}{6}
Problem 3: m=0m = 0
Problem 4: Undefined
Bonus Problem: The mistake was incorrectly calculating the numerator. The correct slope is m=125m = -\frac{12}{5}

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