The problem is to expand the expression $(3x + 2)^2$.

AlgebraAlgebraic ExpansionBinomial TheoremQuadratic Expression
2025/4/27

1. Problem Description

The problem is to expand the expression (3x+2)2(3x + 2)^2.

2. Solution Steps

We can use the formula for the square of a binomial:
(a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2
In this case, a=3xa = 3x and b=2b = 2.
So,
(3x+2)2=(3x)2+2(3x)(2)+(2)2(3x + 2)^2 = (3x)^2 + 2(3x)(2) + (2)^2
Now, we calculate each term:
(3x)2=9x2(3x)^2 = 9x^2
2(3x)(2)=12x2(3x)(2) = 12x
(2)2=4(2)^2 = 4
Putting it all together, we get:
(3x+2)2=9x2+12x+4(3x + 2)^2 = 9x^2 + 12x + 4

3. Final Answer

9x2+12x+49x^2 + 12x + 4