The problem asks us to graph the linear equation $y = 3x - 1$.

1. Problem Description

The problem asks us to graph the linear equation $y = 3x - 1$.

2. Solution Steps

To graph the equation $y = 3x - 1$, we need to find at least two points that satisfy this equation.

First, let's find the $y$-intercept. This occurs when $x = 0$. Substituting $x = 0$ into the equation gives us:

$y = 3(0) - 1$

$y = -1$

So, the first point is $(0, -1)$.

Next, let's find the $x$-intercept. This occurs when $y = 0$. Substituting $y = 0$ into the equation gives us:

$0 = 3x - 1$

$3x = 1$

$x = \frac{1}{3}$

So, the second point is $(\frac{1}{3}, 0)$.

Alternatively, we can choose any arbitrary value for $x$ and find the corresponding $y$ value. For example, let $x = 1$. Then,

$y = 3(1) - 1$

$y = 3 - 1$

$y = 2$

So, the third point is $(1, 2)$.

We can plot any two of these points and draw a straight line through them. The easiest points to use are often the $y$-intercept $(0, -1)$ and the point $(1, 2)$.

3. Final Answer

$y = 3x - 1$