The problem asks us to find the slope and $y$-intercept of a given line on a graph. Then, we need to use these values to write the equation of the line in slope-intercept form.

AlgebraLinear EquationsSlope-Intercept FormCoordinate Geometry
2025/3/6

1. Problem Description

The problem asks us to find the slope and yy-intercept of a given line on a graph. Then, we need to use these values to write the equation of the line in slope-intercept form.

2. Solution Steps

First, we need to find two points on the line. From the graph, we can identify the points (5,0)(-5, 0) and (0,1)(0, 1).
Next, we can find the slope mm using the formula:
m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}
Using the points (5,0)(-5, 0) and (0,1)(0, 1), we have:
m=100(5)=15m = \frac{1 - 0}{0 - (-5)} = \frac{1}{5}
The yy-intercept is the point where the line crosses the yy-axis, which is (0,1)(0, 1). Thus, b=1b = 1.
The slope-intercept form of a line is given by:
y=mx+by = mx + b
Substituting the values we found for mm and bb, we get:
y=15x+1y = \frac{1}{5}x + 1

3. Final Answer

y-intercept: (0,1)(0, 1)
Slope: 15\frac{1}{5}
Equation of the line:
y=15x+1y = \frac{1}{5}x + 1

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