The problem asks us to find the domain of the function $d(x) = 4 - \frac{1}{2}x$ for the range $\{0, \frac{5}{2}, 4.5\}$. In other words, we need to find the $x$ values that correspond to $d(x) = 0$, $d(x) = \frac{5}{2}$, and $d(x) = 4.5$.

AlgebraFunctionsDomain and RangeLinear Equations
2025/3/6

1. Problem Description

The problem asks us to find the domain of the function d(x)=412xd(x) = 4 - \frac{1}{2}x for the range {0,52,4.5}\{0, \frac{5}{2}, 4.5\}. In other words, we need to find the xx values that correspond to d(x)=0d(x) = 0, d(x)=52d(x) = \frac{5}{2}, and d(x)=4.5d(x) = 4.5.

2. Solution Steps

First, we find the xx value when d(x)=0d(x) = 0:
0=412x0 = 4 - \frac{1}{2}x
12x=4\frac{1}{2}x = 4
x=8x = 8
Second, we find the xx value when d(x)=52d(x) = \frac{5}{2}:
52=412x\frac{5}{2} = 4 - \frac{1}{2}x
12x=452\frac{1}{2}x = 4 - \frac{5}{2}
12x=8252\frac{1}{2}x = \frac{8}{2} - \frac{5}{2}
12x=32\frac{1}{2}x = \frac{3}{2}
x=3x = 3
Third, we find the xx value when d(x)=4.5d(x) = 4.5:
4.5=412x4.5 = 4 - \frac{1}{2}x
92=412x\frac{9}{2} = 4 - \frac{1}{2}x
12x=492\frac{1}{2}x = 4 - \frac{9}{2}
12x=8292\frac{1}{2}x = \frac{8}{2} - \frac{9}{2}
12x=12\frac{1}{2}x = -\frac{1}{2}
x=1x = -1
Therefore, the domain for the given range is 8,3,18, 3, -1.

3. Final Answer

1,3,8-1, 3, 8

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