The problem asks us to find the slope and y-intercept of the given line and then write the equation of the line in slope-intercept form.

AlgebraLinear EquationsSlope-Intercept FormCoordinate Geometry
2025/3/7

1. Problem Description

The problem asks us to find the slope and y-intercept of the given line and then write the equation of the line in slope-intercept form.

2. Solution Steps

First, we need to identify two points on the line from the graph. Let's choose the points (0,4)(0, -4) and (4,2)(4, -2).
Next, we calculate the slope mm using the formula:
m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}
Using the points (0,4)(0, -4) and (4,2)(4, -2), we have:
m=2(4)40=2+44=24=12m = \frac{-2 - (-4)}{4 - 0} = \frac{-2 + 4}{4} = \frac{2}{4} = \frac{1}{2}
The slope mm is 12\frac{1}{2}.
Now, we need to find the y-intercept. The y-intercept is the point where the line crosses the y-axis. From the graph, we can see that the line crosses the y-axis at the point (0,4)(0, -4). Therefore, the y-intercept bb is 4-4.
Finally, we can write the equation of the line in slope-intercept form, which is y=mx+by = mx + b.
Substituting the values of mm and bb, we get:
y=12x4y = \frac{1}{2}x - 4

3. Final Answer

y=12x4y = \frac{1}{2}x - 4

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