The problem asks to identify the correct definition of the derivative from first principles. The options are variations of the limit definition of the derivative.

AnalysisCalculusDerivativesLimitsFirst Principles
2025/5/14

1. Problem Description

The problem asks to identify the correct definition of the derivative from first principles. The options are variations of the limit definition of the derivative.

2. Solution Steps

The derivative of a function f(x)f(x) from first principles (also known as the limit definition of the derivative) is defined as:
f(x)=limh0f(x+h)f(x)hf'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h}
Here, hh is a small change in xx, which is often represented as δx\delta x in some notations. Replacing hh by δx\delta x, we have:
f(x)=limδx0f(x+δx)f(x)δxf'(x) = \lim_{\delta x \to 0} \frac{f(x+\delta x) - f(x)}{\delta x}
In the given question, the options are expressed in terms of dydx\frac{dy}{dx}. The derivative is the same as f(x)f'(x), so we have:
dydx=limδx0f(x+δx)f(x)δx\frac{dy}{dx} = \lim_{\delta x \to 0} \frac{f(x+\delta x) - f(x)}{\delta x}
Now, we compare the given options to this formula.
(A) dydx=limδxf(x+δx)+f(x)δx\frac{dy}{dx} = \lim_{\delta x \to \infty} \frac{f(x+\delta x) + f(x)}{\delta x} is incorrect. The limit should approach 0, not infinity, and it should be a difference, not a sum, in the numerator.
(B) dydx=limδxf(δx)f(x)δx\frac{dy}{dx} = \lim_{\delta x \to \infty} \frac{f(\delta x) - f(x)}{\delta x} is incorrect. The function evaluated at x+δxx+\delta x is needed, and the limit should approach

0. (C) The option is cut off and we cannot see it fully.

(D) dydx=limδxf(x+δx)f(x)f(δx)+f(x)\frac{dy}{dx} = \lim_{\delta x \to \infty} \frac{f(x+\delta x) - f(x)}{f(\delta x)+ f(x)} is incorrect. The denominator should be δx\delta x and the limit should approach
0.
None of the given options are correct with the limit tending to infinity. However, we need to choose the 'best' answer, by assuming there is a typographical error. The correct formula has δx0\delta x \to 0 and f(x+δx)f(x)δx\frac{f(x+\delta x) - f(x)}{\delta x}.
Option (B) has most of it right. So let us assume the limit should be δx0\delta x \to 0. Also assume the numerator in (B) should read f(x+δx)f(x)f(x+\delta x) - f(x). Then it would be correct.
Therefore, based on the options, (B) is the closest to the correct definition of the derivative from first principles if we assume that the limit approaches 0 and it contains f(x+δx)f(x+\delta x) rather than f(δx)f(\delta x).

3. Final Answer

(B)

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