The problem asks to find the inverse element for the operation $*$ defined as $x * y = \frac{2x + 2y + 1}{2}$. We first need to find the identity element $e$ such that $x * e = x$. Then, we need to find the inverse element $x'$ such that $x * x' = e$.

AlgebraAbstract AlgebraInverse ElementIdentity ElementBinary Operation
2025/3/8

1. Problem Description

The problem asks to find the inverse element for the operation * defined as xy=2x+2y+12x * y = \frac{2x + 2y + 1}{2}. We first need to find the identity element ee such that xe=xx * e = x. Then, we need to find the inverse element xx' such that xx=ex * x' = e.

2. Solution Steps

First, we find the identity element ee. We require xe=xx * e = x for all xx. Thus,
2x+2e+12=x\frac{2x + 2e + 1}{2} = x
2x+2e+1=2x2x + 2e + 1 = 2x
2e=12e = -1
e=12e = -\frac{1}{2}
Now we find the inverse element xx' such that xx=e=12x * x' = e = -\frac{1}{2}.
xx=2x+2x+12=12x * x' = \frac{2x + 2x' + 1}{2} = -\frac{1}{2}
2x+2x+1=12x + 2x' + 1 = -1
2x=2x22x' = -2x - 2
x=x1x' = -x - 1

3. Final Answer

x=x1x' = -x - 1

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