The problem asks us to estimate the total number of passengers transported by airline S, given that the total passenger transportation volume of airline S is 18.747 million kilometers and the average transportation distance per passenger is 5,500 kilometers. We are to choose the closest value from the following options: 34,750, 341,000, 612,000, 3,408,000, 6,124,000.

Applied MathematicsEstimationWord ProblemUnits ConversionDivision
2025/6/8

1. Problem Description

The problem asks us to estimate the total number of passengers transported by airline S, given that the total passenger transportation volume of airline S is 18.747 million kilometers and the average transportation distance per passenger is 5,500 kilometers. We are to choose the closest value from the following options: 34,750, 341,000, 612,000, 3,408,000, 6,124,
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2. Solution Steps

The total passenger transportation volume is given by the number of passengers multiplied by the average transportation distance per passenger. We are given the total passenger transportation volume of airline S is 18.747 million kilometers or 18.747×10618.747 \times 10^6 kilometers. The average transportation distance per passenger is 5,500 kilometers. Let NN be the number of passengers transported.
We have:
N×5500=18.747×106N \times 5500 = 18.747 \times 10^6
N=18.747×1065500=1874700055003408.545N = \frac{18.747 \times 10^6}{5500} = \frac{18747000}{5500} \approx 3408.545
Since the units of the transportation volume is millions of kilometers, NN is in millions. Therefore, the number of passengers transported by S airline is about 3.408 million or 3,408,
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3. Final Answer

3,408,000

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