The problem asks to calculate the final velocity of a moving car, given its initial velocity, acceleration, and distance traveled, using the equation $v^2 = u^2 + 2as$. The initial velocity $u$ is 30 m/s, the acceleration $a$ is 5 m/s², and the distance $s$ is 320 m.

1. Problem Description

The problem asks to calculate the final velocity of a moving car, given its initial velocity, acceleration, and distance traveled, using the equation $v^2 = u^2 + 2as$. The initial velocity $u$ is 30 m/s, the acceleration $a$ is 5 m/s², and the distance $s$ is 320 m.

2. Solution Steps

First, substitute the given values into the equation $v^2 = u^2 + 2as$.

$v^2 = (30)^2 + 2 * (5) * (320)$

$v^2 = 900 + 3200$

$v^2 = 4100$

Then, take the square root of both sides to find the final velocity $v$.

$v = \sqrt{4100}$

$v = \sqrt{100*41}$

$v = 10\sqrt{41}$

$v \approx 64.03$ m/s

3. Final Answer

The final velocity of the moving car is approximately 64.03 m/s.