Simplify the expression $-6\sqrt{\frac{3y^2}{16}}$.

AlgebraSimplificationRadicalsAbsolute ValueExponents
2025/6/17

1. Problem Description

Simplify the expression 63y216-6\sqrt{\frac{3y^2}{16}}.

2. Solution Steps

We can rewrite the expression as:
63y216-6 \sqrt{\frac{3y^2}{16}}
We can separate the square root of a fraction into the fraction of the square roots:
ab=ab\sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}}
Applying this, we have:
63y216-6 \frac{\sqrt{3y^2}}{\sqrt{16}}
We can further separate the square root of a product into the product of the square roots:
ab=ab\sqrt{ab} = \sqrt{a} \sqrt{b}
Applying this, we have:
63y216-6 \frac{\sqrt{3} \sqrt{y^2}}{\sqrt{16}}
Since y2=y\sqrt{y^2} = |y| and 16=4\sqrt{16} = 4, we have:
63y4-6 \frac{\sqrt{3}|y|}{4}
We can simplify the fraction by dividing both the numerator and denominator by 2:
33y2-3 \frac{\sqrt{3}|y|}{2}
Combining the constants, we have:
332y-\frac{3\sqrt{3}}{2}|y|

3. Final Answer

332y-\frac{3\sqrt{3}}{2}|y|

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