The image contains several math problems. I will solve "Example 1" and "Related Problem 1". Example 1: A sequence is formed by adding consecutive integers to 1. The sequence is 1, 2, 4, 7, 11, 16, ... What is the 15th number in the sequence? Related Problem 1: In the sequence from Example 1, what is the 20th number?

AlgebraSequencesSeriesSummationArithmetic SeriesFormula Derivation
2025/6/17

1. Problem Description

The image contains several math problems. I will solve "Example 1" and "Related Problem 1".
Example 1: A sequence is formed by adding consecutive integers to

1. The sequence is 1, 2, 4, 7, 11, 16, ... What is the 15th number in the sequence?

Related Problem 1: In the sequence from Example 1, what is the 20th number?

2. Solution Steps

Example 1:
The sequence is formed by adding consecutive integers starting from 1 to the previous term.
1st term: 1
2nd term: 1 + 1 = 2
3rd term: 2 + 2 = 4
4th term: 4 + 3 = 7
5th term: 7 + 4 = 11
...
nth term is given by: 1+(1+2+3+...+(n1))1 + (1 + 2 + 3 + ... + (n-1)).
The sum of the first n1n-1 integers is given by the formula:
S=(n1)n2S = \frac{(n-1)n}{2}
Therefore, the nth term is 1+(n1)n21 + \frac{(n-1)n}{2}.
For the 15th term (n=15n=15), the number is:
1+(151)×152=1+14×152=1+7×15=1+105=1061 + \frac{(15-1) \times 15}{2} = 1 + \frac{14 \times 15}{2} = 1 + 7 \times 15 = 1 + 105 = 106
Related Problem 1:
To find the 20th number in the sequence, we substitute n=20n = 20 into the formula:
1+(201)×202=1+19×202=1+19×10=1+190=1911 + \frac{(20-1) \times 20}{2} = 1 + \frac{19 \times 20}{2} = 1 + 19 \times 10 = 1 + 190 = 191

3. Final Answer

Example 1: The 15th number is
1
0

6. Related Problem 1: The 20th number is

1
9
1.

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