The problem consists of two questions. Question 1 asks to evaluate several expressions involving exponents. Question 2 consists of two parts: Part a asks to find the values of some expressions involving exponents, given the value of $x$, and Part b asks to solve an equation.

AlgebraExponentsRadicalsAlgebraic ExpressionsEquation Solving
2025/6/17

1. Problem Description

The problem consists of two questions. Question 1 asks to evaluate several expressions involving exponents. Question 2 consists of two parts: Part a asks to find the values of some expressions involving exponents, given the value of xx, and Part b asks to solve an equation.

2. Solution Steps

Question 1:
i. (0.5)3=(1/2)3=(1)3/23=1/8=0.125(-0.5)^3 = (-1/2)^3 = (-1)^3 / 2^3 = -1/8 = -0.125
ii. 272/3+1=(271/3)2+1=(3)2+1=9+1=1027^{2/3} + 1 = (27^{1/3})^2 + 1 = (3)^2 + 1 = 9 + 1 = 10
We use the formula:
(am)n=amn(a^m)^n = a^{mn}
iii. (25100)1/2+(32)0=(10025)1/2+1=(4)1/2+1=2+1=3(\frac{25}{100})^{-1/2} + (\frac{3}{2})^0 = (\frac{100}{25})^{1/2} + 1 = (4)^{1/2} + 1 = 2 + 1 = 3
We use the formulas:
an=1ana^{-n} = \frac{1}{a^n}
a0=1a^0 = 1
iv. 30×33+3=1×33+3=1×27+3=27+3=303^0 \times 3^3 + 3 = 1 \times 3^3 + 3 = 1 \times 27 + 3 = 27 + 3 = 30
We use the formula:
a0=1a^0 = 1
v. 252÷55=(52)2÷55=54÷55=5455=1525^2 \div 5^5 = (5^2)^2 \div 5^5 = 5^4 \div 5^5 = \frac{5^4}{5^5} = \frac{1}{5}
We use the formula:
aman=amn\frac{a^m}{a^n} = a^{m-n}
vi. 23×21+x0=8×12+1=4+1=52^3 \times 2^{-1} + x^0 = 8 \times \frac{1}{2} + 1 = 4 + 1 = 5, assuming x0x \neq 0.
We use the formulas:
an=1ana^{-n} = \frac{1}{a^n}
a0=1a^0 = 1
Question 2:
a. Given x=2516x = \frac{25}{16}
i. x0=(2516)0=1x^0 = (\frac{25}{16})^0 = 1
ii. x1/2=(2516)1/2=2516=2516=54x^{1/2} = (\frac{25}{16})^{1/2} = \sqrt{\frac{25}{16}} = \frac{\sqrt{25}}{\sqrt{16}} = \frac{5}{4}
iii. x3/2=(2516)3/2=(1625)3/2=((1625)1/2)3=(45)3=4353=64125x^{-3/2} = (\frac{25}{16})^{-3/2} = (\frac{16}{25})^{3/2} = ((\frac{16}{25})^{1/2})^3 = (\frac{4}{5})^3 = \frac{4^3}{5^3} = \frac{64}{125}
b. 6x+2=23\frac{6}{x+2} = \frac{2}{3}
Cross-multiplying, we get:
6×3=2×(x+2)6 \times 3 = 2 \times (x+2)
18=2x+418 = 2x + 4
2x=1842x = 18 - 4
2x=142x = 14
x=7x = 7

3. Final Answer

Question 1:
i. -0.125
ii. 10
iii. 3
iv. 30
v. 1/5
vi. 5
Question 2:
a.
i. 1
ii. 5/4
iii. 64/125
b. x = 7

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