最新の問題

The problem asks to find the endpoints of the midsegment of trapezoid $ABCD$, where $AD$ is parallel...

TrapezoidMidsegmentCoordinate GeometryMidpoint Formula
2025/3/13

Solve for $x$ in the equation $\frac{2}{3}x - \frac{5}{6} = \frac{3}{4}$.

Linear EquationsFractionsSolving Equations
2025/3/13

We are given a kite $WXYZ$. We are given $m\angle WXY = 120^\circ$, $m\angle WZY = (4x)^\circ$, and ...

KiteQuadrilateralAngle PropertiesAngle SumSolving Equations
2025/3/13

We are given a trapezoid $ABCD$. We are given that $m\angle ABC = (4x + 11)^\circ$ and $m\angle DAB ...

TrapezoidIsosceles TrapezoidAngle PropertiesAlgebra
2025/3/13

The problem states that $ABCD$ is an isosceles trapezoid. The length of diagonal $AC$ is given by $3...

Isosceles TrapezoidDiagonalsEquation SolvingAlgebra
2025/3/13

点A, B, Dが同一水平面上にあり、$\angle CAD = 60^\circ$, $\angle DAB = 75^\circ$, $\angle DBA = 60^\circ$, $AB = ...

三角比正弦定理角度距離高さ直角三角形
2025/3/13

The problem asks to classify quadrilaterals as trapezoids, isosceles trapezoids, or kites, based on ...

QuadrilateralsTrapezoidsIsosceles TrapezoidsKitesGeometric PropertiesShape Classification
2025/3/13

The problem states that in trapezoid $ABCD$, $PQ$ is the midsegment. Given that $DC = 18$ and $PQ = ...

TrapezoidMidsegmentGeometric Formulas
2025/3/13

We are given a trapezoid $HJKT$. $TS$ is the midsegment of the trapezoid. We are given that $HJ = 14...

TrapezoidMidsegmentGeometric Formulas
2025/3/13

$\theta$が鈍角であるとき、以下の問題に答えよ。 (1) $\sin \theta = \frac{1}{3}$のとき、$\cos \theta$と$\tan \theta$の値を求めよ。 (2...

三角比三角関数鈍角sincostan相互関係
2025/3/13