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最新の問題

We are asked to simplify the expression $\frac{a^{\frac{1}{2}} \times a^{\frac{1}{4}}}{a}$.

ExponentsSimplificationFractionsAlgebraic Expressions
2025/3/8

Simplify the expression $\sqrt[3]{a^2} \times \sqrt{a^{-3}}$.

ExponentsRadicalsSimplificationFractional Exponents
2025/3/8

The problem is to evaluate the expression $(\frac{1}{32})^{\frac{-4}{3}}$.

ExponentsRadicalsSimplification
2025/3/8

The problem is to simplify the expression $1 \div 2 \cdot \sqrt{x^{-3}}$.

SimplificationRadicalsExponentsRationalization
2025/3/8

The problem is to determine the domain of the function $f(x) = \frac{1}{2\sqrt{x-3}}$.

DomainFunctionsSquare RootInequalities
2025/3/8

The problem is to simplify the expression $\frac{1}{2\sqrt{x^{-8}}}$.

SimplificationExponentsRadicals
2025/3/8

Simplify the expression $\frac{2^3 \times 2^{-3}}{2^2}$.

ExponentsSimplificationFractions
2025/3/8

数列 $\{c_n\}$ が $c_1 = 2^{\frac{1}{4}}$ および漸化式 $c_{n+1} = \frac{2^{\frac{1}{8}n + \frac{1}{4}}}{c_n}$...

数列漸化式一般項和指数関数
2025/3/8

数列 $\{c_n\}$ が、$c_1 = 2\frac{1}{4} = \frac{9}{4}$ と漸化式 $c_{n+1} = \frac{2\frac{1}{8}n + \frac{1}{4}}...

漸化式数列の一般項数列の和
2025/3/8

数列 $\{c_n\}$ が、$c_1 = 2^{\frac{1}{4}}$, $c_{n+1} = \frac{2^{\frac{1}{8}n + \frac{1}{4}}}{c_n}$ $(n=1...

数列漸化式一般項数学的帰納法Σ計算
2025/3/8
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