The problem is to simplify the expression $\sin^2(x) + \sin(x)\cos(x)$.

TrigonometryTrigonometric IdentitiesSimplificationSineCosine
2025/4/26

1. Problem Description

The problem is to simplify the expression sin2(x)+sin(x)cos(x)\sin^2(x) + \sin(x)\cos(x).

2. Solution Steps

We can factor out sin(x)\sin(x) from both terms:
sin2(x)+sin(x)cos(x)=sin(x)(sin(x)+cos(x))\sin^2(x) + \sin(x)\cos(x) = \sin(x)(\sin(x) + \cos(x))
Alternatively, we can multiply and divide by 2 the second term to try to use trigonometric identities.
sin2(x)+sin(x)cos(x)=sin2(x)+12(2sin(x)cos(x))\sin^2(x) + \sin(x)\cos(x) = \sin^2(x) + \frac{1}{2}(2\sin(x)\cos(x))
Using the double angle identity:
sin(2x)=2sin(x)cos(x) \sin(2x) = 2\sin(x)\cos(x)
we get
sin2(x)+12sin(2x) \sin^2(x) + \frac{1}{2}\sin(2x)
This expression is also a correct simplification.
However, sin(x)(sin(x)+cos(x))\sin(x)(\sin(x) + \cos(x)) seems like the more natural simplification of the original expression.

3. Final Answer

sin(x)(sin(x)+cos(x))\sin(x)(\sin(x) + \cos(x))

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