The problem states that the sum of two consecutive whole numbers is $\frac{5}{6}$ of their product. We need to find those two numbers among the given options.

1. Problem Description

The problem states that the sum of two consecutive whole numbers is $\frac{5}{6}$ of their product. We need to find those two numbers among the given options.

2. Solution Steps

Let's check each option:

A. The numbers are 3 and

4. Sum: $3 + 4 = 7$

Product: $3 \times 4 = 12$

Is $7 = \frac{5}{6} \times 12$?

$7 = \frac{5 \times 12}{6} = \frac{60}{6} = 10$

$7 \ne 10$, so this option is incorrect.

B. The numbers are 1 and

2. Sum: $1 + 2 = 3$

Product: $1 \times 2 = 2$

Is $3 = \frac{5}{6} \times 2$?

$3 = \frac{5 \times 2}{6} = \frac{10}{6} = \frac{5}{3}$

$3 \ne \frac{5}{3}$, so this option is incorrect.

C. The numbers are 2 and

3. Sum: $2 + 3 = 5$

Product: $2 \times 3 = 6$

Is $5 = \frac{5}{6} \times 6$?

$5 = \frac{5 \times 6}{6} = 5$

$5 = 5$, so this option is correct.

D. The numbers are 0 and

1. Sum: $0 + 1 = 1$

Product: $0 \times 1 = 0$

Is $1 = \frac{5}{6} \times 0$?

$1 = 0$, so this option is incorrect.

3. Final Answer

C. 2, 3