We are asked to find the limit of the function $x^2 + xe^x$ as $x$ approaches infinity. That is, we need to find $A = \lim_{x \to \infty} (x^2 + xe^x)$.

AnalysisLimitsCalculusInfinityExponential Functions
2025/5/2

1. Problem Description

We are asked to find the limit of the function x2+xexx^2 + xe^x as xx approaches infinity. That is, we need to find A=limx(x2+xex)A = \lim_{x \to \infty} (x^2 + xe^x).

2. Solution Steps

We need to evaluate the limit of the function x2+xexx^2 + xe^x as xx approaches infinity.
Since x2x^2 and xexxe^x both tend to infinity as xx goes to infinity, we can consider them separately and then add the results. Specifically,
limxx2=\lim_{x \to \infty} x^2 = \infty.
Also, limxxex=\lim_{x \to \infty} xe^x = \infty.
Therefore, limx(x2+xex)=limxx2+limxxex=+=\lim_{x \to \infty} (x^2 + xe^x) = \lim_{x \to \infty} x^2 + \lim_{x \to \infty} xe^x = \infty + \infty = \infty.
More formally, since both terms go to infinity as xx approaches infinity, their sum also goes to infinity.

3. Final Answer

\infty

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