The problem requires us to find the equation of a line given its slope and y-intercept, and to express the equation in slope-intercept form. We are given the slope $m = \frac{4}{7}$ and the y-intercept $(0, -2)$. The slope-intercept form is $y = mx + b$, where $m$ is the slope and $b$ is the y-coordinate of the y-intercept.

AlgebraLinear EquationsSlope-Intercept Form
2025/3/6

1. Problem Description

The problem requires us to find the equation of a line given its slope and y-intercept, and to express the equation in slope-intercept form. We are given the slope m=47m = \frac{4}{7} and the y-intercept (0,2)(0, -2). The slope-intercept form is y=mx+by = mx + b, where mm is the slope and bb is the y-coordinate of the y-intercept.

2. Solution Steps

We are given the slope m=47m = \frac{4}{7} and the y-intercept (0,2)(0, -2), so b=2b = -2.
The slope-intercept form of a linear equation is
y=mx+by = mx + b
Substituting the given values:
y=47x+(2)y = \frac{4}{7}x + (-2)
y=47x2y = \frac{4}{7}x - 2

3. Final Answer

y=47x2y = \frac{4}{7}x - 2

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