The problem describes a rectangular playing field with a given perimeter of 372 yards. The length of the field is 2 yards less than triple the width. We need to find the dimensions (length and width) of the playing field.

1. Problem Description

The problem describes a rectangular playing field with a given perimeter of 372 yards. The length of the field is 2 yards less than triple the width. We need to find the dimensions (length and width) of the playing field.

2. Solution Steps

Let $w$ represent the width of the rectangular field, and let $l$ represent the length.

We are given that the perimeter $P$ is 372 yards. The formula for the perimeter of a rectangle is:

$P = 2l + 2w$

We are also given that the length $l$ is 2 yards less than triple the width $w$. So, we can write the length as:

$l = 3w - 2$

Now we can substitute the expression for $l$ into the perimeter formula:

$372 = 2(3w - 2) + 2w$

$372 = 6w - 4 + 2w$

$372 = 8w - 4$

Add 4 to both sides:

$376 = 8w$

Divide both sides by 8:

$w = \frac{376}{8} = 47$

Now that we have the width, we can find the length:

$l = 3w - 2 = 3(47) - 2$

$l = 141 - 2 = 139$

So, the width is 47 yards and the length is 139 yards.

3. Final Answer

$w = 47$

$l = 139$