We want to find the limit of $2^{-x}$ as $x$ approaches infinity. In other words, we need to find $\lim_{x \to \infty} 2^{-x}$.

AnalysisLimitsExponential FunctionsCalculus
2025/5/6

1. Problem Description

We want to find the limit of 2x2^{-x} as xx approaches infinity. In other words, we need to find limx2x\lim_{x \to \infty} 2^{-x}.

2. Solution Steps

We can rewrite 2x2^{-x} as 12x\frac{1}{2^x}.
So, we want to find limx12x\lim_{x \to \infty} \frac{1}{2^x}.
As xx approaches infinity, 2x2^x also approaches infinity. Therefore, we have:
limx12x=1=0\lim_{x \to \infty} \frac{1}{2^x} = \frac{1}{\infty} = 0

3. Final Answer

0

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