We are asked to find the value of the expression $\frac{6^{1/2} \cdot 9^{1/4}}{216^{1/4}}$.

AlgebraExponentsRadicalsSimplification
2025/3/19

1. Problem Description

We are asked to find the value of the expression 61/291/42161/4\frac{6^{1/2} \cdot 9^{1/4}}{216^{1/4}}.

2. Solution Steps

We simplify the expression:
61/291/42161/4=61/2(32)1/4(63)1/4=61/232/463/4=61/231/263/4=(63)1/263/4=181/263/4=(232)1/2(23)3/4=21/232/223/433/4=21/2323/433/4=212343134=2243434434=21/431/4=31/421/4=(32)1/4\frac{6^{1/2} \cdot 9^{1/4}}{216^{1/4}} = \frac{6^{1/2} \cdot (3^2)^{1/4}}{(6^3)^{1/4}} = \frac{6^{1/2} \cdot 3^{2/4}}{6^{3/4}} = \frac{6^{1/2} \cdot 3^{1/2}}{6^{3/4}} = \frac{(6 \cdot 3)^{1/2}}{6^{3/4}} = \frac{18^{1/2}}{6^{3/4}} = \frac{(2 \cdot 3^2)^{1/2}}{(2 \cdot 3)^{3/4}} = \frac{2^{1/2} \cdot 3^{2/2}}{2^{3/4} \cdot 3^{3/4}} = \frac{2^{1/2} \cdot 3}{2^{3/4} \cdot 3^{3/4}} = 2^{\frac{1}{2} - \frac{3}{4}} \cdot 3^{1 - \frac{3}{4}} = 2^{\frac{2}{4} - \frac{3}{4}} \cdot 3^{\frac{4}{4} - \frac{3}{4}} = 2^{-1/4} \cdot 3^{1/4} = \frac{3^{1/4}}{2^{1/4}} = (\frac{3}{2})^{1/4}

3. Final Answer

(c) (32)1/4(\frac{3}{2})^{1/4}

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