Two parallel lines are intersected by a transversal. One angle is given as $76^\circ$. We need to find the measure of angle $x$.

1. Problem Description

Two parallel lines are intersected by a transversal. One angle is given as $76^\circ$. We need to find the measure of angle $x$.

2. Solution Steps

Since the two lines are parallel, the corresponding angles are equal. Let's call the angle corresponding to the $76^\circ$ angle as $a$. Thus, $a = 76^\circ$.

The angles $a$ and $x$ are supplementary angles, which means they add up to $180^\circ$.

$x + a = 180^\circ$

$x + 76^\circ = 180^\circ$

$x = 180^\circ - 76^\circ$

$x = 104^\circ$

3. Final Answer

$x = 104^\circ$