The problem asks us to identify which of the given equations have $a=8$ as a solution. We need to choose 3 answers.

AlgebraSolving EquationsSubstitutionSingle Variable Equations
2025/3/6

1. Problem Description

The problem asks us to identify which of the given equations have a=8a=8 as a solution. We need to choose 3 answers.

2. Solution Steps

We need to substitute a=8a=8 into each equation and see if it is a valid solution.
A. a+11=15a+11 = 15. Substituting a=8a=8, we get 8+11=198+11 = 19. Since 191519 \neq 15, a=8a=8 is not a solution.
B. 1=8÷a1 = 8 \div a. Substituting a=8a=8, we get 1=8÷8=11 = 8 \div 8 = 1. Since 1=11=1, a=8a=8 is a solution.
C. 15+a=2315+a = 23. Substituting a=8a=8, we get 15+8=2315+8 = 23. Since 23=2323=23, a=8a=8 is a solution.
D. 42=7a42 = 7a. Substituting a=8a=8, we get 42=7×8=5642 = 7 \times 8 = 56. Since 425642 \neq 56, a=8a=8 is not a solution.
E. a5=3a-5 = 3. Substituting a=8a=8, we get 85=38-5 = 3. Since 3=33=3, a=8a=8 is a solution.

3. Final Answer

B, C, E

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