The problem is to analyze the exponential function $f(x) = 3 \cdot 2^x$. The image shows the graph coordinate system, and the function is plotted.

AnalysisExponential FunctionsFunction AnalysisGraphing
2025/5/7

1. Problem Description

The problem is to analyze the exponential function f(x)=32xf(x) = 3 \cdot 2^x. The image shows the graph coordinate system, and the function is plotted.

2. Solution Steps

To understand the function, we can evaluate it for a few values of xx:
If x=0x = 0, then f(0)=320=31=3f(0) = 3 \cdot 2^0 = 3 \cdot 1 = 3.
If x=1x = 1, then f(1)=321=32=6f(1) = 3 \cdot 2^1 = 3 \cdot 2 = 6.
If x=2x = 2, then f(2)=322=34=12f(2) = 3 \cdot 2^2 = 3 \cdot 4 = 12.
If x=1x = -1, then f(1)=321=312=32=1.5f(-1) = 3 \cdot 2^{-1} = 3 \cdot \frac{1}{2} = \frac{3}{2} = 1.5.
If x=2x = -2, then f(2)=322=314=34=0.75f(-2) = 3 \cdot 2^{-2} = 3 \cdot \frac{1}{4} = \frac{3}{4} = 0.75.
The graph will pass through the points (0,3)(0, 3), (1,6)(1, 6), (2,12)(2, 12), (1,1.5)(-1, 1.5), and (2,0.75)(-2, 0.75). The graph will increase rapidly as xx increases, and approach 00 as xx goes to negative infinity.

3. Final Answer

The function is f(x)=32xf(x) = 3 \cdot 2^x. We can analyze the behavior of this exponential function by plugging in some values of x.

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