The problem asks us to find the derivative of the function $y = -x^3(3x^4 - 2)$.

AnalysisDifferentiationPower RuleDerivativesCalculus
2025/5/8

1. Problem Description

The problem asks us to find the derivative of the function y=x3(3x42)y = -x^3(3x^4 - 2).

2. Solution Steps

First, we distribute the x3-x^3 term:
y=3x7+2x3y = -3x^7 + 2x^3
Now, we apply the power rule for differentiation, which states that if y=axny = ax^n, then dydx=naxn1\frac{dy}{dx} = nax^{n-1}.
Applying the power rule to the first term, 3x7-3x^7, we get:
ddx(3x7)=3(7)x71=21x6\frac{d}{dx}(-3x^7) = -3(7)x^{7-1} = -21x^6
Applying the power rule to the second term, 2x32x^3, we get:
ddx(2x3)=2(3)x31=6x2\frac{d}{dx}(2x^3) = 2(3)x^{3-1} = 6x^2
Adding the derivatives of the two terms gives the derivative of yy:
dydx=21x6+6x2\frac{dy}{dx} = -21x^6 + 6x^2

3. Final Answer

dydx=21x6+6x2\frac{dy}{dx} = -21x^6 + 6x^2

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