We are given a matrix equation $[2p \quad 3]\begin{bmatrix} 4 \\ -6 \end{bmatrix} = [6]$ and need to find the value of $p$.

AlgebraMatrix AlgebraLinear EquationsSolving Equations
2025/5/9

1. Problem Description

We are given a matrix equation [2p3][46]=[6][2p \quad 3]\begin{bmatrix} 4 \\ -6 \end{bmatrix} = [6] and need to find the value of pp.

2. Solution Steps

First, perform the matrix multiplication:
[2p3][46]=(2p)(4)+(3)(6)=8p18[2p \quad 3]\begin{bmatrix} 4 \\ -6 \end{bmatrix} = (2p)(4) + (3)(-6) = 8p - 18.
Now, we can set this result equal to 6:
8p18=68p - 18 = 6.
Next, add 18 to both sides of the equation:
8p=6+188p = 6 + 18
8p=248p = 24.
Finally, divide both sides by 8 to solve for pp:
p=248p = \frac{24}{8}
p=3p = 3.

3. Final Answer

The value of pp is 3.

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