We are asked to solve the expression $(2+\sqrt{-4})(-1+\sqrt{-9})$.

1. Problem Description

We are asked to solve the expression $(2+\sqrt{-4})(-1+\sqrt{-9})$.

2. Solution Steps

First, we simplify the square roots of negative numbers using the imaginary unit $i$, where $i = \sqrt{-1}$.

We have $\sqrt{-4} = \sqrt{4 \cdot -1} = \sqrt{4} \cdot \sqrt{-1} = 2i$.

Similarly, $\sqrt{-9} = \sqrt{9 \cdot -1} = \sqrt{9} \cdot \sqrt{-1} = 3i$.

Now substitute these values back into the expression:

$(2 + 2i)(-1 + 3i)$.

Next, we expand the product using the distributive property (FOIL):

$(2)(-1) + (2)(3i) + (2i)(-1) + (2i)(3i) = -2 + 6i - 2i + 6i^2$.

Since $i^2 = -1$, we have $6i^2 = 6(-1) = -6$.

Combining the terms, we get:

$-2 + 6i - 2i - 6 = -2 - 6 + 6i - 2i = -8 + 4i$.

3. Final Answer

$-8 + 4i$