The problem asks us to determine if the function $f(x) = \cos(x)$ is even or odd. We need to evaluate $f(-x)$.

AnalysisFunctionsEven and Odd FunctionsTrigonometryCosine Function
2025/5/17

1. Problem Description

The problem asks us to determine if the function f(x)=cos(x)f(x) = \cos(x) is even or odd. We need to evaluate f(x)f(-x).

2. Solution Steps

To determine if a function is even or odd, we need to examine f(x)f(-x).
If f(x)=f(x)f(-x) = f(x), the function is even.
If f(x)=f(x)f(-x) = -f(x), the function is odd.
If neither of these is true, the function is neither even nor odd.
Given f(x)=cos(x)f(x) = \cos(x), we need to find f(x)f(-x).
f(x)=cos(x)f(-x) = \cos(-x)
Since the cosine function is an even function, we know that cos(x)=cos(x)\cos(-x) = \cos(x).
Therefore, f(x)=cos(x)=cos(x)=f(x)f(-x) = \cos(-x) = \cos(x) = f(x).
Since f(x)=f(x)f(-x) = f(x), the function f(x)=cos(x)f(x) = \cos(x) is an even function.

3. Final Answer

f(x)=cos(x)f(-x) = \cos(x), thus f(x)f(x) is an even function.

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