The image contains several math problems. I will solve problem "ក" (first problem). It asks to calculate the limit of the function $2e^x - xe^x + 2e^x + 4$ as $x$ approaches 0. That is: $\lim_{x\to 0} (2e^x - xe^x + 2e^x + 4)$.

AnalysisLimitsCalculusExponential Functions
2025/5/20

1. Problem Description

The image contains several math problems. I will solve problem "ក" (first problem). It asks to calculate the limit of the function 2exxex+2ex+42e^x - xe^x + 2e^x + 4 as xx approaches

0. That is: $\lim_{x\to 0} (2e^x - xe^x + 2e^x + 4)$.

2. Solution Steps

We need to evaluate the limit of the function as xx approaches

0. The function is $f(x) = 2e^x - xe^x + 2e^x + 4$.

We can simplify it as f(x)=4exxex+4f(x) = 4e^x - xe^x + 4.
Since the exponential function is continuous, we can directly substitute x=0x = 0 into the function to evaluate the limit.
limx0(4exxex+4)=4e00e0+4\lim_{x \to 0} (4e^x - xe^x + 4) = 4e^0 - 0 \cdot e^0 + 4
We know that e0=1e^0 = 1.
So, the limit is 4(1)0(1)+4=40+4=84(1) - 0(1) + 4 = 4 - 0 + 4 = 8.

3. Final Answer

The limit of the function 2exxex+2ex+42e^x - xe^x + 2e^x + 4 as xx approaches 0 is
8.

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