The problem asks us to rewrite the equation $4x + \frac{3}{4}y = -3$ in slope-intercept form, which is $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept.

1. Problem Description

The problem asks us to rewrite the equation $4x + \frac{3}{4}y = -3$ in slope-intercept form, which is $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept.

2. Solution Steps

We are given the equation $4x + \frac{3}{4}y = -3$.

We want to isolate $y$ on one side of the equation.

First, subtract $4x$ from both sides:

$\frac{3}{4}y = -4x - 3$

Next, multiply both sides by $\frac{4}{3}$ to solve for $y$:

$y = \frac{4}{3}(-4x - 3)$

$y = \frac{4}{3}(-4x) + \frac{4}{3}(-3)$

$y = -\frac{16}{3}x - 4$

3. Final Answer

$y = -\frac{16}{3}x - 4$