The problem asks to find the slope and y-intercept of the line whose graph is shown, and then write the equation of the line.

AlgebraLinear EquationsSlopeY-interceptGraphing
2025/3/6

1. Problem Description

The problem asks to find the slope and y-intercept of the line whose graph is shown, and then write the equation of the line.

2. Solution Steps

From the graph, we can identify two points on the line. Let's approximate these points as (0,12)(0, 12) and (1,3)(1, 3).
The slope mm of the line passing through the points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by the formula:
m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}
Substituting the coordinates of the points (0,12)(0, 12) and (1,3)(1, 3) into the formula, we have:
m=31210=91=9m = \frac{3 - 12}{1 - 0} = \frac{-9}{1} = -9
Thus, the slope of the line is 9-9.
The y-intercept is the point where the line intersects the y-axis, which is the point (0,12)(0, 12). Therefore, the y-intercept bb is 1212.
The equation of a line in slope-intercept form is given by:
y=mx+by = mx + b
Substituting the slope m=9m = -9 and the y-intercept b=12b = 12 into the equation, we get:
y=9x+12y = -9x + 12

3. Final Answer

Slope = -9
y=9x+12y = -9x + 12

Related problems in "Algebra"