The problem is to find the sum of the infinite series $\sum_{k=1}^{\infty} \frac{1}{k^3}$.

AnalysisInfinite SeriesRiemann Zeta FunctionApery's ConstantConvergence
2025/3/9

1. Problem Description

The problem is to find the sum of the infinite series k=11k3\sum_{k=1}^{\infty} \frac{1}{k^3}.

2. Solution Steps

The given series is k=11k3\sum_{k=1}^{\infty} \frac{1}{k^3}. This is a p-series with p=3p=3.
A p-series is defined as
k=11kp\sum_{k=1}^{\infty} \frac{1}{k^p}
The p-series converges if p>1p>1 and diverges if p1p \le 1.
In this case, p=3p=3, so the series converges.
The series k=11k3\sum_{k=1}^{\infty} \frac{1}{k^3} is a specific case of the Riemann zeta function, defined as ζ(s)=k=11ks\zeta(s) = \sum_{k=1}^{\infty} \frac{1}{k^s}.
Therefore, we have k=11k3=ζ(3)\sum_{k=1}^{\infty} \frac{1}{k^3} = \zeta(3).
The value of ζ(3)\zeta(3) is Apéry's constant, which is an irrational number. There is no known closed-form expression for ζ(3)\zeta(3) in terms of other known constants like π\pi or ee. Its approximate value is 1.202056903159594285399738161511449990764986292...
Thus, the sum of the series is ζ(3)\zeta(3).

3. Final Answer

ζ(3)\zeta(3)

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