The problem is to evaluate the expression $(\frac{n^3}{-4})^3$.

1. Problem Description

The problem is to evaluate the expression $(\frac{n^3}{-4})^3$.

2. Solution Steps

We are asked to simplify the expression $(\frac{n^3}{-4})^3$.

We can use the property that $(a/b)^n = a^n/b^n$. Therefore,

$(\frac{n^3}{-4})^3 = \frac{(n^3)^3}{(-4)^3}$.

Now we simplify the numerator and denominator separately.

For the numerator, we have $(n^3)^3 = n^{3*3} = n^9$.

For the denominator, we have $(-4)^3 = (-4) * (-4) * (-4) = 16 * (-4) = -64$.

Putting these together, we have

$\frac{(n^3)^3}{(-4)^3} = \frac{n^9}{-64} = -\frac{n^9}{64}$.

3. Final Answer

$-\frac{n^9}{64}$