The problem asks us to graph the linear equation $4x + 5y = 20$ on the given coordinate plane. We are given that the slope $m = -4/5$ and the y-intercept $b = 4$.

1. Problem Description

The problem asks us to graph the linear equation $4x + 5y = 20$ on the given coordinate plane. We are given that the slope $m = -4/5$ and the y-intercept $b = 4$.

2. Solution Steps

To graph the equation, we can use the slope-intercept form of a line, which is $y = mx + b$. We already have the slope $m = -4/5$ and the y-intercept $b = 4$.

Thus, the equation can be written as $y = (-4/5)x + 4$.

The y-intercept is the point where the line crosses the y-axis, which is $(0, 4)$.

To find another point on the line, we can use the slope. The slope is $-4/5$, which means for every 5 units we move to the right (increase in x), we move 4 units down (decrease in y).

Starting from the y-intercept $(0, 4)$, we can move 5 units to the right to $x = 5$. The corresponding y value would be $4 + (-4/5)(5) = 4 - 4 = 0$. So, another point on the line is $(5, 0)$, which is the x-intercept.

Now we have two points $(0, 4)$ and $(5, 0)$.

Plot the points $(0, 4)$ and $(5, 0)$ on the coordinate plane and draw a line that passes through both points.

3. Final Answer

The line is shown on the graph by plotting $(0, 4)$ and $(5, 0)$ and drawing a line through them.

The line passes through the points (0,4) and (5,0).