The problem asks to find the y-intercept and x-intercepts of the quadratic equation $y = x^2 - 2x - 15$.

1. Problem Description

The problem asks to find the y-intercept and x-intercepts of the quadratic equation $y = x^2 - 2x - 15$.

2. Solution Steps

To find the y-intercept, we set $x = 0$ and solve for $y$.

$y = (0)^2 - 2(0) - 15$

$y = -15$

So the y-intercept is at the point $(0, -15)$.

To find the x-intercepts, we set $y = 0$ and solve for $x$.

$0 = x^2 - 2x - 15$

We can factor the quadratic expression:

$0 = (x - 5)(x + 3)$

Setting each factor equal to zero:

$x - 5 = 0$ or $x + 3 = 0$

$x = 5$ or $x = -3$

So the x-intercepts are at the points $(5, 0)$ and $(-3, 0)$.

3. Final Answer

The y-intercept is $(0, -15)$.

The x-intercepts are $(5, 0)$ and $(-3, 0)$.